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A hydraulic press has one piston of diameter 2.0cm and the other piston of diameter 8.0cm what force must be applied to the smaller piston to obtain a force of 1600 N at the larger piston. |
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Answer» We know that P1 = \(\frac{F_1}{A_1}\) then P2 = P1 \(\frac{F_2}{A_2}=\frac{F_1}{A_1}\) \(F_2 = A_2\times\frac{F_1}{A_1}\) \(F_2=\pi r_2^2 \times \frac{F_1}{\pi r_1^2}\) \(F_2=F_1(\frac{r_2}{r_1})^2\) \(F_2 = 1600\times(\frac{0.04}{0.01})^2\) \(F_2 = 1600\times16\) F2 = 25600 N |
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