A hydrocarbon C_3H_6 (A) reacts with HBr to form compound (B). Compound (B) reacts with aqueous potassium hydroxide to give (C) of molecular formula C_3H_8O. What are (A) (B) and (C ). Explain the reactions.

A hydrocarbon C_3H_6 (A) reacts with HBr to form compound (B). Compoun

1.	A hydrocarbon C_3H_6 (A) reacts with HBr to form compound (B). Compound (B) reacts with aqueous potassium hydroxide to give (C) of molecular formula C_3H_8O. What are (A) (B) and (C ). Explain the reactions.
Answer» SOLUTION : (i)The hydrocarbon with molecular formula `C_3H_6` (A) is identified as propene. `CH_3 - CH = CH_2`. (ii) Propene reacts with HBR to FORM bromopropane `CH_3 - CH_2 - CH_2Br` as (B). (iii) 1-bromopropane react with aqueous POTASSIUM hydroxide to give l-propanol `CH_3-CH_2 - CH_2OH` as (C ). (iv) 2-bromo propane reacts with aqueous KOH to give 2-propanol as (C)