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A hydrogen electrode is prepared by using a sample of HCl solution with `pH=4` and `H_(2)` gas at 1 atm pressure. What is the electrode potential of the electrode?A. 0.814 VB. 0.236 VC. `-0.06V`D. `-0.618V`

Answer» Correct Answer - B
`E=E^(@)-(0.0591)/(n)log[H^(+)]=0-(0.0591)/(1)log10^(-4)=0.236V`


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