A hydrogen gas electrode is mae by dipping platinum wire in a solution of HCl of pH=10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would beA. 1.81 VB. 0.059VC. 0.59VD. 0.118V

A hydrogen gas electrode is mae by dipping platinum wire in a solution

1.	A hydrogen gas electrode is mae by dipping platinum wire in a solution of HCl of pH=10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would beA. 1.81 VB. 0.059VC. 0.59VD. 0.118V
Answer» Correct Answer - C `(1)/(2)H_(2)(g)toH^(+)+e^(-)` `E_(O.P.)=E_(O.P.)^(o)-(0.059)/(n)log([H^(+)])/((P_(H_(2)))^(1//2))` `E_(O.P.)=0-(0.059)/(1)"log"(10^(-10))/((1)^(1//2))(pH=10,[H^(+)]=10^(-10)M)` `E_(O.P.)=0.59V`

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A hydrogen gas electrode is mae by dipping platinum wire in a solution of HCl of pH=10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would beA. 1.81 VB. 0.059VC. 0.59VD. 0.118V

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