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A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n. It can emit a photon of maximum energy 204 eV. If it makes a transition to quantum state n, a photon of energy 40.8 eV is emitted. The value of n will be. |
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Answer» A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n. It can emit a photon of maximum energy 204 eV. If it makes a transition to quantum state n, a photon of energy 40.8 eV is emitted. The value of n will be |
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