1.

A hydrogenation reaction is carrid out at 500 K. If the same reaction is carried out in the presence of a catalyst at the same rate, the termperature required is 400 K. Calculatethe activation energy of the reaction if the catalyst lowers the activation barrier by 20 kj mol^(-1).

Answer»

Solution :RATE of hydrogenation at `500^@K` for a REACTION is equal to the rateof reaction in presense of catalyst at `400^@ K`
Rate = k `xx` conc of REACTANT
If rate of reaction are equal therefore their rate constant will also form Arrhenius equation
`k = AE^(-E_a//RT)`
`k_500 =Ae^(-(E-a//RT)`...(i)`k_400 = Ae^(-E_a//RT_2)`...(ii)
When `k_500 = k_400`
`:.((E_0)_1)/(RT_1) = ((E_a)_2)/(RT_2)`(From eqs (i) and (ii))or `((E_a)_1)/((E_a)_2) = T_1/T_2`
`E_(a_1)/E_(a_2)=T_1/T_2 = 500/400 = 5/4`... (i)
In presence of catalyst`E_a`decreases by 20 kJ `mol^(-1)`
So,`E_a_1 = 100kJ//mol^(-1)`
`E_a_2 = 80 KJ//mol^(-1)`
Hence, `E_a` or reaction OS `100kJ mol^(-1)`


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