1.

A hyperbola passing through a focus of the ellipse x^(2)/(169)+y^(2)/(25)=1. Its transverse and conjugate axes coincide respectively with the major and minor axes of the ellipse. The product of eccentricities is 1. Then, the equation of the hyperbola is,

Answer»

`X^(2)/(144)-y^(2)/(9)=1`
`x^(2)/(169)-y^(2)/(25)=1`
`x^(2)/(144)-y^(2)/(25)=1`
`x^(2)/(25)-y^(2)/(9)=1`

Answer :C


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