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A hypothetical reaction `:` `A_(2)+B_(2)rarr 2AB` Follows mechanism as given below `:` `A_(2) overset(k_(c))hArr A+A................(` fast `)" "(k_(C)-` is equilibrium constant ) `A+B_(2)overset(k_(1))rarrAB+B...............(" slow")" "(k_(1)-` rate constant ) `A+B underset(K_(2))overset(k_(2))hArrAB...............(` fast `)" "(k_(2),k_(3)-` are rate constant`)` Give the rate law.A. `r=k_(1)sqrt(k_(c))[A_(2)]^(1//2)[B_(2)]`B. `r=(k_(1))/(k_(c))[A_(2)]^(1//2)[B_(2)]`C. `r=sqrt(k_(1)k_(c))[A_(2)]^(1//2)[B_(2)]`D. `r=(k_(1))/(sqrt(k_(c)))[A_(2)]^(1//2)[B_(2)]` |
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Answer» Correct Answer - A Rate of governed by slowest step `A+B overset(k_(1))rarr AB+B` `r=k_(1)[A][B_(2)]" "……(i)` From `A_(2)overset(k_(c))hArrA+A` `k_(c)=([A]^(2))/([A_(2)])" ".....(ii)` `[A]=sqrt(k_(c))[A_(2)]^(1//2)` `r=k_(1)sqrt(k_(c))[A_(2)]^(1//2)[B_(2)]" order is "=(1)/(2)+1=(3)/(2)` |
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