1.

A hypothetical reaction, A_(2)+B_(2)to2 AB, follows the mechanism as given below : A_(2)iff A+A""("Fast") A+B_(2)to AB+B""("Slow") A+BtoAB""("Fast") The overall order of reaction is

Answer»

zero
1
`1(1)/(2)`
2

Solution :As RATE depends upon the SLOW step,
Rate `= k[A][B_(2)]`
for the equilibrium, `iff 2A , K_(c) = ([A]^(2))/([A_(2)])`
or `[A]=sqrt(K_(c)[A_(2)])`
` therefore` Rate `=k K_(c)^(1//2) [A_(2)]^(1//2)[B_(2)] = k'[A_(2)]^(1//2)[B_(2)]`
Hence, order `= (1)/(2) + 1 = 1""(1)/(2).`


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