InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
(a) (i) Complete the following chemical equations : (i)`NaOH_((aq))+Cl_(2(g)) rightarrow` (Hot and conc.) (ii) `Xef_(6)(s)+H_(2)O(l) rightarrow` (b) How would you account for the following ? (i) The value of electron gain enthalpy with negative sign for sulphur is higher than that for oxygen. (ii) `NF_(3)` is an exothermic compound but `NCl_(3)` is endothermic compound. (iii)`ClF_(3)` molecule has a T-shaped structure and not a trigonal planar one. |
|
Answer» (a)(i) `6NaOH +3Cl_(2) rightarrow 5 NaCl +NaCl O_(3)+ 3H_(2)O` (ii)` Xe F_(6)+ H_(2)O rightarrow Xe OF_(4)+2HF` (b) (i) Because of larger size of sulphur atom than oxygen atom. (ii) Because bond energy of `F_(2)` is lowerthan `Cl_(2)` and N-F bond is smaller and stronger than N-Cl bond. (iii) Because it has `dsp^(3)` hybridization. |
|