InterviewSolution
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InterviewSolution
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(a) (i) Out of coke and CO_3, which is better reducing agent for the reduction of ZaO ? Why? (ii) An element (A) extracted from kernite. A reacts with nitrogen at high temperature give B.A reacts with alkali to from C . Find out A, B and C Give the chemical equations. [OR] (b) (i)Deduce the oxidation number oxygen in hypoflgynous acid-HOF. (ii) Which catalyst is used in the conversion of acetaldehyde to acetic acid ? Given equation . |
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Answer» Solution :(i) COKE. (C) is a BETTER reducing agent for the reduction of ZnO . Because , when we use coke, the reduction can be EASILY carried out at 673 K. Thus carbon (Coke) reduces zinc oxide more easily than carbon monoxide (CO). From the Ellingham diagrams , it is quite clear that the reduction of zinc oxide is more favorable using coke (`DeltaG` for the formation of carbon monoxide from carbon is more negative ). (ii)An element (A) extracted fromkernite is boron. `"*"` Boron reacts with nitrogen at high temperatures to give Boron nitride (B) `underset((A))(2B)+N_2overset(Delta)rarrunderset((B))(2BN)` `"*"` Boron reacts with alkali (NaOH) to give sodium borate (C) . `underset((A))(2B)+underset(("Sodiumbydroxide"))(6NaOH)rarrunderset((C))(2Na_3BO_3+3H_2)` `{:(A,"Boron",B),(B,"Boron nitride",BN),(C,"Sodium borate",Na_3BO_3):}` (b)  In CASE of O - F bond is HOF , fluorine is most electronegative element . So its oxidation number is - 1 . Therefore oxidation number of O is +1 . Similarly in case of O - H bond is HOF. O is highly electronegative than H. So its oxidation number is - 1 and oxidation number of H is + 1 . So Net oxidation of oxygen is - 1 + 1 = 0 . (ii) `underset("Acetaldehyde")(CH_3-CHO+O)overset(Rh//Ir"complex")underset("oxidation")rarrCH_3-underset("Acetic acid")(COOH)` |
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