a) i) write the equations for the steps in SN1 mechanism of the conversion of tertiary butyl bromide in to tertiary butyl alcohol. ii) Haloarenes are less reactive towards nucleophilic substitution reactions than Haloalkanes. Give a reason.

a) i) write the equations for the steps in SN1 mechanism of the conver

1.	a) i) write the equations for the steps in SN1 mechanism of the conversion of tertiary butyl bromide in to tertiary butyl alcohol. ii) Haloarenes are less reactive towards nucleophilic substitution reactions than Haloalkanes. Give a reason.
Answer» Solution :a) The mechanism involves the following two steps. Step 1: Formation of carbocation: t-butyl bromide undergoes ionization to form a t-butyl carbocation. This step is the slowest step hence it is the rate determining step. Step - 2 : Attack of nucleophile on the carbocation : The nucleophile `OH^(-)` can attack the carbocation either from from front side or back side to form t - butyl alcohol. This step is fast. `THEREFORE` Rate of the reaction is directly `alpha" [ t - butyl bromide]"^(1)[OH^(-)]^(0)` `therefore` ORDER = 1 ii) Haloarences are resonance STABILISED with carbon halogen double bond.