

InterviewSolution
Saved Bookmarks
1. |
(a) If the cell emp is -1.58 V what is the concentrtion of `Zn^(+2) (b) "If" NH_(3)` added to half cel A how emf of cel will change ? `E_(Ag^(+)//Ag)^(@)=0.8 V,E_(Zn^(+23)//Zn)^(@)=0.76 V` Antilog (0.6768) =1.4768 |
Answer» (a) `[Zn^(+2)]=0.0241 M` (b) emp increase | |