1.

A is 60% more efficient than B. In how many days will A and B together complete a piece of work if A alone can complete the work in 15 days?1). $$9\frac{7}{13}$$2). $$8\frac{9}{13}$$3). $$8\frac{4}{13}$$4). $$10\frac{1}{13}$$

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Solution

Time TAKEN by A alone = 15 days

Efficiency of A : B = 100 : 160

= 15 : 24

=> Time taken by B = 24 days

$\THEREFORE$ (A + B)'s 1 day's work

= $\FRAC{1}{15} + \frac{1}{24}$

= $\frac{8 + 5}{120} = \frac{13}{120}$

$\therefore$ Required time = $\frac{1}{\frac{13}{120}}$

= $\frac{120}{13} = 9\frac{3}{13}$ days



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