A is twice efficient of B. If A takes 60 days less than B, then how ma

1.	A is twice efficient of B. If A takes 60 days less than B, then how many days required to complete work. When they work together?1. 30 days2. 50 days3. 40 days4. 20 days5. None of these
Answer» Correct Answer - Option 3 : 40 days Given: Efficiency ratio of A and B = 2 ∶ 1 Condition = A takes 60 days less than B Formula: W = E × T Here, W = work E = Efficiency T = Time Calculation: We know that – E ∝ 1/T (w = constant) Efficiency Ratio of A & B = 2 : 1 Days Ratio of A & B = 1 : 2 Now, 2 – 1 = 60 1 = 60 Now, A = 1 ×60 A = 60 days B = 2 ×60 B = 120 Now, LCM (60, 120) = 120 unit Efficiency of A and B together = 2 + 1 = 3 Required time = 120/3 Required time = 40 days ∴ They completed the work together in 40 days.

A is twice efficient of B. If A takes 60 days less than B, then how many days required to complete work. When they work together?1. 30 days2. 50 days3. 40 days4. 20 days5. None of these

Answer» Correct Answer - Option 3 : 40 days

Given:

Efficiency ratio of A and B = 2 ∶ 1

Condition = A takes 60 days less than B

Formula:

W = E × T

Here,

W = work

E = Efficiency

T = Time

Calculation:

We know that –

E ∝ 1/T (w = constant)

Efficiency Ratio of A & B = 2 : 1

Days Ratio of A & B = 1 : 2

Now,

2 – 1 = 60

1 = 60

Now,

A = 1 ×60

A = 60 days

B = 2 ×60

B = 120

Now,

LCM (60, 120) = 120 unit

Efficiency of A and B together = 2 + 1 = 3

Required time = 120/3

Required time = 40 days

∴ They completed the work together in 40 days.

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