InterviewSolution
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InterviewSolution
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(a)IV lslThe dipole moment of HBr is 2.6x10-0 cmand the interatomic spacing is 1.41A. The percentage ofionic character in HBr is:0(a) 10.5(b) 11.5(c) 12.5(d) 13.5If t |
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Answer» We know ,HBr is an ionic compound in which H has + 1 and Br has -1 ion e.g charge one each have equal to charge of one electron or charge of proton .dipole moment =charge x distance between them =1.6 x 10^-19 x 141 x 10^-12 Cm=225.6 x 10^-31 Cm=22.56 x 10^-30 Cmnow,% of ionic characters =dipole moment by experimental/dipole moment by theoretical x100=(2.6 x 10^-30/22.56 x 10^-30 ) x 100=260/22.56 %=11.52 % Thanks |
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