A J-shaped tube with smaller end closed and longer end open was taken. Mercury was added into it till the level of mercury in both the limbs was same. Volume of air enclosed in the closed end was found to be 2.4 mL. Now more mercury was added and the air enclosed in the closed ed reduced to 1.9 mL. Now, the difference in the level of the two limbs will be

A J-shaped tube with smaller end closed and longer end open was taken.

1.	A J-shaped tube with smaller end closed and longer end open was taken. Mercury was added into it till the level of mercury in both the limbs was same. Volume of air enclosed in the closed end was found to be 2.4 mL. Now more mercury was added and the air enclosed in the closed ed reduced to 1.9 mL. Now, the difference in the level of the two limbs will be
Answer» <html><body><p>43 cm<br/>5 cm <br/>10 cm <br/>20 cm </p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_01_XI_C05A_E13_009_S01.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a>, `P_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=<a href="https://interviewquestions.tuteehub.com/tag/760-335611" style="font-weight:bold;" target="_blank" title="Click to know more about 760">760</a>" mm", V_(1)=2.4" mL"` <br/> Finally, `P_(2)=?, V_(2)=1.9" mL"` <br/> `P_(1)V_(1)=P_(2)V_(2)" or "P_(2)=(P_(1)V_(1))/(V_(2))` <br/> `=(760xx2.4)/(1.9)=960" mm Hg"` <br/> `:.` Difference in the two <a href="https://interviewquestions.tuteehub.com/tag/limbs-1073960" style="font-weight:bold;" target="_blank" title="Click to know more about LIMBS">LIMBS</a> =960-760 mm=200 mm=20 cm</body></html>