1.

A jeep starts from the stateof rest. If its velocity becoms 60km/hr in 5minute. What is the acceleration of jeep?what is the distance covered by the jeep?

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YOUR ANSWER IS

acceleration= velocity/time

60km/hr = 60 km /60 mins = 1km/min so accn = 1km/5= 1000m/5 = 200m/m

v²= u²+2as

(1000)² = 0²+ 2 X 200 x s

(1000)²/400= s

2500m



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