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A jug contains 2L of milk. Calcualte the volume of the milk in `m^(3)` |
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Answer» Since 1L = `1000 cm ^(3)` and 1m = 100 cm , which gives `(1m)/(100 cm) =1 = (1 m^(3))/(1 m) ` TO get `m^(3) ` from the above unit factors , the first unit factor is taken ant it is cubed `((1m)/(100 cm ))^(3) implies (1 m^(3))/(10^(6) cm^(3))=(1)^(3) =1 ` Now 2 L `= 2xx1000 cm^(3)` the above is multiplied by the unit factor `2xx1000 cm^(3) xx(1 m^(3))/(10 ^(6)cm^(3)) =(2 m^(3))/(10^(3)) = 2xx10^(-3) m^(3)` |
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