a. Ketone (A) which undergoes haloform reaction gives compound (B) on reduction. (B) on heating with sulphuric acid gives compounds (C ) which forms monozonide (D). (D) on hydrolysis in the presence of Zn dust gives only acetaldehyde. Identify (A), (B), (C ). b. C_(6)H_(14)O (A) on heating with KOH and I_(2) gives yellow precipitate (A) on dehydration using Al_(2)O_(3) gives (B) which on catalytic hydration gives (C ) which gives Lucas test readily. Identify (A), (B), and (C ). c. Compound (A) C_(5)H_(10)O forms a phenylhydrazone and gives a negative Tollens and negative iodoform tests. (A) on reduction gives n-pentane. Identify A. d. One gram mixture of CH_(3)OH and CH_(3)CHO reacts with Bendict's reagent to give a red precipitate. Themass of the red precipitate obtained is 1/43 gm. Calculate the % of CH_(3)CHO in the mixture.

a. Ketone (A) which undergoes haloform reaction gives compound (B) on

1.	a. Ketone (A) which undergoes haloform reaction gives compound (B) on reduction. (B) on heating with sulphuric acid gives compounds (C ) which forms monozonide (D). (D) on hydrolysis in the presence of Zn dust gives only acetaldehyde. Identify (A), (B), (C ). b. C_(6)H_(14)O (A) on heating with KOH and I_(2) gives yellow precipitate (A) on dehydration using Al_(2)O_(3) gives (B) which on catalytic hydration gives (C ) which gives Lucas test readily. Identify (A), (B), and (C ). c. Compound (A) C_(5)H_(10)O forms a phenylhydrazone and gives a negative Tollens and negative iodoform tests. (A) on reduction gives n-pentane. Identify A. d. One gram mixture of CH_(3)OH and CH_(3)CHO reacts with Bendict's reagent to give a red precipitate. Themass of the red precipitate obtained is 1/43 gm. Calculate the % of CH_(3)CHO in the mixture.
Answer» Solution :a. `{:(Aimplies,"2-Butan-2-ONE",,Bimplies,"Butan-2-ol"),(Cimplies,"But-2-ene",,Dimplies,"But-2-enozonide"):}` c. `Aimplies 3`-Pentan-3-one b. Benedict's regent reacts only with `CH_(2)CHO`. One mole of `CH_(3)CHO` gives 1 MOL `Cu_(2)O. (Mw of CH_(3)CHO=44 gm), (Mw of Cu_(2)O=143 gm) 143 gm` of `Cu_(2)O` is obtained from `44 gm` of `CH_(3)CHO` `1.43 gm` of `Cu_(2)O` is obtained from `IMPLIES (44xx1.43)/143` `implies 0.44 G. of CH_(3)CHO` `%` of `CH_(3)CHO=0.44/1xx100 =44%`