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A `KMnO_(4)` solution can be standarised by titration against `As_(2)O_(3(s))`. A `0.1156 g` sample of `As_(2)O_(3)` requires `27.06mL` of the `KMnO_(4(aq.))` for its titration. What is the molarity of the `KMnO_(4(aq.))` [As `=75`]? `5As_(2)O_(3)+4MnO_(4)^(-)+9H_(2)O+12H^(+)rarr10H_(2)AsO_(4)+4Mn^(2+)` |
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Answer» Meq.of `As_(2)O_(3)=` Meq.of `KMnO_(4)` `(As_(2)^(3+)rarr2As^(5+)rarr4e)` `(0.1156)/(198//4)xx1000=Mxx5xx27.08` `(Mn^(7+)+5erarrMn^(2+))` `therefore M=0.0172` `therefore M_(MnO_(4)^(-))=0.0172M` |
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