1.

A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.

Answer»

In ⊥∆ACB, ∠C = 90°, BC = ? 

AC2 + CB2 = AB2 

(8)2 + CB2 = (10)2 

64 + CB2 = 100 

CB2 = 100 – 64 

CB2 = 36 

∴ CB = 6 

∴ Ladder is at a distance of 6m from the base of the wall.



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