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A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall. |
Answer» In ⊥∆ACB, ∠C = 90°, BC = ? AC2 + CB2 = AB2 (8)2 + CB2 = (10)2 64 + CB2 = 100 CB2 = 100 – 64 CB2 = 36 ∴ CB = 6 ∴ Ladder is at a distance of 6m from the base of the wall. |
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