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A ladder of length `l` carrying a man of mass `m` at its end is attached to the basket of a balloon of mass M. The entire system is in equilibrium in the air. As the man climbs up the ladder into the balloon, the balloon descends by a height h. The potential energy of the manA. (a) Increases by `mg(l-h)`B. (b) Increases by `mgl`C. (c) Increases by `mgh`D. (d) Increases by `mg(2l-h)` |
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Answer» Correct Answer - A When the man climbs the ladder of length l, the balloon descends by height h. So net height gained by the man is `l-h`. Hence, gain in potential energy of the man is `mg(l-h)`. Work done by man: `W_1=mgl` Inclination in potential energy of balloon=work done by man -increase in potential energy of man, i.e., `mgl-mg(l-h)=mgh` |
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