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A large and small vehicle moving with the some kinetic energy on a straight road. Their engine are simultaneously OFF. Which one will stop at a longer distance ? |
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Answer» Solution :The vehicle stops when k.E is spent in working against the FORCE of friction varies directly with the weight of the vehicle. k.E = workdone Workdone (W) = Force of friction `xx` distance Energy € `= f xx s` Displacement (S) = E/f For given k.E s will be smaller where F is LARGER such as in the SMALL vehicle, so the displacement of a larger vehicle is HIGH. |
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