1.

A lead piece of mass 25 g gives out 1200 calories of heat when it is cooled from 90^(@)C to 10^(@)C. What is its i) Specific heat ii) thermal capacity and iii) Water equivalent.

Answer»

Solution :MASS of lead piece (m) = 25 G = 0.025 kg
AMOUNT of heat GIVEN out = 1200 calories
Amount of heat energy given out (dQ) = `1200xx4.2J`
The fall in temperature (dT) = `(90-10)^(@)C=80^(@)C=80K`
(i) Specific heat S = `1/m(dQ)/(dT)=1/0.025xx(1200xx4.2)/80`
= `5040/2=2520Jkg^(-1)K^(-1)`
(ii) Thermal capacity = MS = `0.025xx2520=63JK^(-1)`
(iii) Water equivalent = W = `63/4200kg`


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