A lead storage battery has initially 200 g of holf and 200 g of PbO_(2), plus excess H_(2)SO_(4). Theoretically, how long could this cell deliver a current of 10 amp, without reacharging, if it were possible to operate it so that the reaction goes to completion.

A lead storage battery has initially 200 g of holf and 200 g of PbO_(2

1.	A lead storage battery has initially 200 g of holf and 200 g of PbO_(2), plus excess H_(2)SO_(4). Theoretically, how long could this cell deliver a current of 10 amp, without reacharging, if it were possible to operate it so that the reaction goes to completion.
Answer» Solution :Discharging of battery takes place through the reaction `{:(Pb,+,PbO_(2),+,2H_(2)SO_(4),=, 2PbSO_(4),+,2H_(2)O),((200)/(207) "mole",,(200)/(239) "mole",,"(excess)",,,,):}` As mole of `PbO_(2)` is less than that of Pb, `PbO_(2)` is the limiting REACTANT which shall be totally CONSUMED. No. of FARADAY delivered by the battery = no. of eq. of `PbO_(2)` lost `= (200)/(239) xx 2` `therefore` charge `= (400)/(239) xx 96500` coulombs `therefore` time of discharge `= (400 xx 96500)/(239) xx (1)/(10)` seconds `= (400 xx 96500)/(239 xx 10) xx (1)/(60 xx 60) h` = 4.486 h.