A Leclanche cell of emf 1.46 V balances against 292 cm of a potentio m

1.	A Leclanche cell of emf 1.46 V balances against 292 cm of a potentio meter wire. If the current through the wire is 400 mA, the resistance per unit length of the potentiometer wire is
Answer» \(\frac{E_1}{l_1}=I\lambda\) \(\therefore \lambda=\frac{E_1}{Il_1}\) \(=\frac{1.46}{(0.4)(2.92)}\) \(\lambda=\frac{1.46}{1.168}\) \(\lambda=1.25\Omega/m\)

A Leclanche cell of emf 1.46 V balances against 292 cm of a potentio meter wire. If the current through the wire is 400 mA, the resistance per unit length of the potentiometer wire is

Answer»

\(\frac{E_1}{l_1}=I\lambda\)

\(\therefore \lambda=\frac{E_1}{Il_1}\)

\(=\frac{1.46}{(0.4)(2.92)}\)

\(\lambda=\frac{1.46}{1.168}\)

\(\lambda=1.25\Omega/m\)

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A Leclanche cell of emf 1.46 V balances against 292 cm of a potentio meter wire. If the current through the wire is 400 mA, the resistance per unit length of the potentiometer wire is

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