

InterviewSolution
Saved Bookmarks
1. |
A lift is ascending with acceleration (g)/(3). Find the time period of simple pendulum of length L kept in lift. |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> sqrt((<a href="https://interviewquestions.tuteehub.com/tag/3l-310759" style="font-weight:bold;" target="_blank" title="Click to know more about 3L">3L</a>)/(g))`<br/>`pi sqrt((3L)/(g))`<br/>`2pi sqrt((3L)/(2g))`<br/>`2pi sqrt((2L)/(3g))`</p>Solution :`implies g_(eff)= g-(g)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)= (2g)/(3)` <br/> `therefore T= 2pi sqrt((L)/(g_(eff)))= 2pi sqrt((L)/(2g"/"3))` <br/> `=2pi sqrt((3L)/(2g))`.</body></html> | |