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A lift is moving up with a constant retardation of 2 m//s^(2). When its upward velocity is 5 m/s, a boy in the lift tosses a coin, imparting it an upward velocity of 3 m/s, w.r.t. himself. His fingers at the moment of toss are midway between the floor and cciling, whose total height is 2 m. Displacement of coin when it hits the ground is x metre (in earth frame). Value of x is : (g = 10 m//s^(2)) |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of coin `= 2 m//s` <br/> Acceleration `= - 10 m//s^(2)` <br/> Now, `h = ut + (1)/(2) a t^(2)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_AM_PHY_C04_E01_221_S01.png" width="80%"/></body></html> | |