InterviewSolution
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InterviewSolution
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A light beam travelling in the `x`-direction is described by the eectirc field `E_(y) = (300 V//m) sin omega(t - x//c)`. An electron is constrained to move along the `y`-direction with a speed of `2.0 xx 10^(7) m//sec`. Find the maximum electric force and the maximum magnetic force on the electron. |
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Answer» `E = E_(0)sin omega (t - x//c)` `E_(0) = 300V//m` `B_(0) = (E_(0))/(c) = (300)/(3xx10^(8)) = 10^(-6)T` `F_(e) = eE_(0) = (1.6 xx 10^(-19)) (300) = 4.8 xx 10^(-17)N` `F_(m) = evB_(0) = 1.6 xx 10^(-19) xx 2xx 10^(7) xx 10^(-6)` `=3.2 xx 10^(-18)N` |
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