1.

A light beam travelling in the x- direction is described by the electric field `E_y(300V (m^-1) sin omega (t-(x//c))`. An electron is constrained to move along the y-direction with a speed`(2.0 xx (10^7) m(s^-1))`. Find the maximum electric force and the maximum magnetic force on the electron.

Answer» Maximum Electric Force
maximum electric field,
`E_0=300 V//m`
maximum electricfoce
`F=qE_0`
`= (1.6xx10^-19)(300)`
`= 4.8xx10^-17 N`
Maximum Magnetic Force
From the equation,
` c=E_0/B_0`
Maximum magnetic field,
or
`B_0 = 300/(3.0xx10^8)=10^-6T`
`:.` maximum magnetic force = `B_0qupsilon`
Substituting the values,we have
maximum magnetic force
`(10^-6)(1.6xx10^-19)(2.0xx10^7)`
` 3.2xx 10^-18 N`.


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