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A light bulb has a resistance of 360 . What is the current in the bulb when it has a potential difference of 120 V across it? 0.33 A 3 A 480 A 43,200 A |
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Answer» tion:The correct answer is OPTION A. 0.33A.According to the Ohm's Law, The current across the TWO points is DIRECTLY propotional to the voltage and the equation is given below.V ∝ i (v is voltage or potential difference and i is current)V = iR ( Resistance)Resistance is a constant, which is independent of the value of the current.Given,R = 360V= 120 VPutting value of R and V in V =iR120 = 360 i\begin{lgathered}\frac{120}{360} =i\\\frac{1}{3} =i\\i=0.33A\end{lgathered} 360120 =i31 =ii=0.33A Hence, the current in the bulb will be 0.33 A (AMPERE). |
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