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A light bulb is rated 200 W for 220 V supply at 50 Hz. Calculate resistance of the bulb and rms current through the bulb. |
Answer» (i) Resistance of the bulb `R=(E^(2))/(P)=((220)^(2))/(200)=242 Omega.` (ii) Peak voltage `V_(0)=Vsqrt(2)=200 sqrt(2)=311 V.` rms current through the bulb, `I=(P)/(E )=(311)/(220)=0.450 A.` |
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