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A light is passed through a sample of a single elecrton excited spice which causes further excitation to some higher energy level and it emit a photon of energy 12.09 eV in back trabsition to some lower energy higher energy level .Then (i)Fing=d out the atomic number of specie ifDebroglie wave lenght of electronin first excited stateis 221.4 pm. (ii) Find out the value of higher energy level and lower energy levelin back transition .

Answer» <html><body><p><br/></p>Solution :(i) `lambda=((<a href="https://interviewquestions.tuteehub.com/tag/150-275254" style="font-weight:bold;" target="_blank" title="Click to know more about 150">150</a>)/(V))^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//2)Å` <br/>`lambda^(2)=(150)/(V)xx10^(-20)` <br/> `V=(150)/(221.54)xx(10^(-20))/(10^(-24))=30.6` <br/>`therefore`(T.E) First excited state=-`13.6((Z^(2))/2^(2))``=-30.6 <a href="https://interviewquestions.tuteehub.com/tag/ev-976207" style="font-weight:bold;" target="_blank" title="Click to know more about EV">EV</a>`<br/> `Z=3 Ans`<br/>(ii) `E_(n2)-E_(<a href="https://interviewquestions.tuteehub.com/tag/n1-1108662" style="font-weight:bold;" target="_blank" title="Click to know more about N1">N1</a>)`= `DeltaE=12.09=13.6xx9((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`<br/>`n_(1)=3`, `n_(2)=<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>`</body></html>


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