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A light particle moving horizontally with a speed of 12 m/s strikes a very heavy block moving in the same direction at 10 m/s. The collision is one dimensional and elastic. After the collision, the particle will be |
| Answer» <html><body><p>move at 2 m/s in its <a href="https://interviewquestions.tuteehub.com/tag/original-1139424" style="font-weight:bold;" target="_blank" title="Click to know more about ORIGINAL">ORIGINAL</a> direction <br/>move at 8 m/s in its original direction <br/>move at 8 m/s opposite to its original direction <br/>move at 12 m/s opposite to its original direction </p>Solution :Here, `u_1 = 12 m//s , u_2 = <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> m//s` <br/> <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> `v_1` be velocity of the light particle after <a href="https://interviewquestions.tuteehub.com/tag/collision-922060" style="font-weight:bold;" target="_blank" title="Click to know more about COLLISION">COLLISION</a>. <br/> `v_1 = ((m_1 -m_2)u_1)/(m_1 + m_2) + (2m_2 u_2)/(m_1 + m_2) "" ……..(i)` <br/> Given : `m_1 < < m_2` <br/> So, `m_1` can be ignored compared to `m_2`. <br/> From equation (i) we get , `v_1 = - u_1 + 2u_2` <br/> Substituting the <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a> , we get <br/> `v_1 = -12 m//s + 2(10 m//s) = 8 m//s` in its original direction.</body></html> | |