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| 1. |
a light ray enters into a liquid at an angle of 45° and gets reflected at an angle of 30° with respect to normal calculate the refractive index of the liquid if sine 45 =0.7 and sin 30°equal to 0.5 |
| Answer» N theta1 = n2 x SIN theta21 x sin 45 = n2 x sin30 (if the 1ST media is air, WHOSE refractive index is 1)0.7 = n2 x 0.5n2 = 7/5n2 = 1.4Mark BRAINLIEST if satisfied | |