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A light ray falls on one of the faces of a prism at an angle 40° so that it suffers angle of minimum deviation of 30°. Find the angle of prism and angle of refraction at the given surface |
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Answer» Given that, incident ray on one of the prisms (i1 ) = 40° Angle of minimum deviation (D) = 30° Angle of prism (A) = ? A+D = 2i1 ⇒ A = 2i1 – D ⇒ A = 2(40°) -30° = 80° – 30° = 50° ∴ Angle of prims (A) = 50° Angle of refraction (r1 ) = ? We know r1 = A/2 [∴ r1 +r2 = A] ⇒r1 = 50°/2 = 25° ∴ Angle of refraction (r1) = 25° |
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