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A light source of wavelength lambdailluminates a metal and ejects photo-electrons with (K.E.)_("max") = 4 eV . Find the value of work function ?

Answer» <html><body><p>1eV<br/>2eV<br/>0.5 eV<br/>None of these</p>Solution :Work function `<a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a>= <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> upsilon_0` <br/>`phi ` for each metal is constant .<br/>if incident <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is <a href="https://interviewquestions.tuteehub.com/tag/known-534098" style="font-weight:bold;" target="_blank" title="Click to know more about KNOWN">KNOWN</a> then `phi` can be calculated.</body></html>


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