1.

A light source of wavelength lambdailluminates a metal and ejects photo-electrons with (K.E.)_("max") = 4 eV . Find the value of work function ?

Answer»

1eV
2eV
0.5 eV
None of these

Solution :Work function `PHI= H upsilon_0`
`phi ` for each metal is constant .
if incident ENERGY is KNOWN then `phi` can be calculated.


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