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A light string of `70cm` has its two ends tied at the same level `50cm` apart. A force of `100N` is applied at a distance of `30cm` from `P` . The tension in part PR is. A. `18N`B. `8N`C. `0N`D. `80N` |
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Answer» Correct Answer - D Here `T_(1)cos(90-theta)`+`T_(2)costheta=100` And `T_(1)costheta=T_(2)cos(90-theta)` Solving, `T_(1)=80N` |
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