A light string passing over a smooth light pulley connects two blocks of masses m_1 and m_2(vertically). If the acceleration of the system is g/8 then the ratio of the masses is

A light string passing over a smooth light pulley connects two blocks

1.	A light string passing over a smooth light pulley connects two blocks of masses m_1 and m_2(vertically). If the acceleration of the system is g/8 then the ratio of the masses is
Answer» `8:1` `9:7` `4:3` `5:3` SOLUTION :The FBD DIAGRAM, the force can be ` m_2a = T -m_2 g"" [a= g/8]` `m_1 a = m_1 g - T` adding we get ` (m_1 + m_2) a = (m_1 - m_2) g ` PUTTING the VALUES, we get `m_1/m_2 = 9/7 `