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A lightmetrescaleis placedhorizontallyon twosupportsat 10cm markand 80 cmmark. If70 gmassIshangedfrom50 cmmark, findforcesupliedby thesupportat 10cmmark, on thescale. |
Answer» Solution : fromthefigure `OA = 10 cm, OB= 50 cm, OC = 80 cm ` ` thereforeAC = OC- OA = 80 -10 = 70cm ` ` BC = OC - OB = 80 - 50 = 30 cm ` `F_(3)= MG= 70xx 980 dyn ` for abodyequilibriumthealgebraicsum of themoments oftheforcesaboutany pointis zero ` therefore `Sumof themomentsof thethreeforcesaboutpointC `G = 0-F_(1 )* AC + F_(3)* BC=0 ` Hence`F_(1)= F_(3) *(BC )/(AC )=(70 xx(80 )xx (3) /(70)=29400dyn ` |
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