1.

A lightmetrescaleis placedhorizontallyon twosupportsat 10cm markand 80 cmmark. If70 gmassIshangedfrom50 cmmark, findforcesupliedby thesupportat 10cmmark, on thescale.

Answer»

Solution :
fromthefigure
`OA = 10 cm, OB= 50 cm, OC = 80 cm `
` thereforeAC = OC- OA = 80 -10 = 70cm `
` BC = OC - OB = 80 - 50 = 30 cm `
`F_(3)= MG= 70xx 980 dyn `
for abodyequilibriumthealgebraicsum of themoments oftheforcesaboutany pointis zero
` therefore `Sumof themomentsof thethreeforcesaboutpointC
`G = 0-F_(1 )* AC + F_(3)* BC=0 `
Hence`F_(1)= F_(3) *(BC )/(AC )=(70 xx(80 )xx (3) /(70)=29400dyn `


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