1.

A line L_(1) with direction ratios -3,2,4 passes through the point A(7,6,2) and a line L_(2) with directions ratios 2,1,3 passes through the point B(5,3,4). A line L_(3) with direction ratios 2,-2,-1 intersects L_(1) and L_(3) at C and D, resectively.The equation of the plane parallel to line L_(1) and containing line L_(2) is equal to

Answer»

`x+3y+4z=30`
`x+2y+z=15`
`2x-y+z=11`
`2x+17y-7z=33`

Solution :Equation of plant parallel to `L_(1)` and containing `L_(2)` is
`a(x-5)+b(y-3)+c(z-4)=0`
`a(x-5)+b(y-3)+c(z-4)=0`
`THEREFORE 2a+b+3c=0` and `-3+2b+4c=0`
`RARR a/-2=b/-17=c/7`
So, required PLANE is `2x+17y-7z=33`.


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