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A linear harmonic oscillator of force constant `2 xx 10^6 N//m` and amplitude (0.01 m) has a total mechanical energy of (160 J). Its.A. maximum potential energy is (100 J)B. maximum kinetic energy is (100 J)C. maximum potential energy is (160 J)D. maximum potential energy is zero. |
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Answer» Correct Answer - B::C The total energy of the oscillator `=(1)/(2) kA^2 = Max.K.E.` `= (1)/(2) xx 2 xx 10^6 xx (0.01)^2 = 100 J` As total mechanical energy = (160 J) The (P.E.) at equilibrium position is not zero. (P.E.) at mean position = `(160 - 100) J = 60 J` :. Max (P.E.) = `(100 + 60) J = 160 J`. |
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