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If `N_(t) = N_(o)e^(lambdat)` then number of disintefrated atoms between `t_(1)` to `t_(2) (t_(2) gt t_(1))` will ve :-A. `N_(o)[e^(lambdat_(2))-e^(lambdat_(3))]`B. `N_(o)[-e^(lambdat_(2)) - e^(-lambdat_(1))]`C. `N_(o)[e^(-lambdat_(1)) - e^(-lambdat_(2))]`D. None of these |
Answer» Correct Answer - C `DeltaN? = N_(1) rarr N_(2) = N_(0)[e^(-lambdat_(1)) - e^(-lambdat_(2))]` |
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