A liquid drop of diameter D breaks up into 27 tiny drops. Find the resulting change in energy. Take surface tension of the liquid as sigma

A liquid drop of diameter D breaks up into 27 tiny drops. Find the res

1.	A liquid drop of diameter D breaks up into 27 tiny drops. Find the resulting change in energy. Take surface tension of the liquid as sigma
Answer» SOLUTION :Radius of larger drop = `(D)/(2)` Radius of each small drop= r `27xx(4)/(3)pir^(3)=(4)/(3)pi((D)/(2))^(2) IMPLIES r=(D)/(6)` Initial surface area of large drop `4pi((D)/(2))^(2)=piD^(2)` Final surface area of 27 small drop `=27xx4pir^(2)=27xx4pi(D^(2))/(36)=3piD^(2)` `:.` CHANGE in energy = Increase in area `xx rho` `=2piD^(2) rho`