1.

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections which have area of cross section A_(1) and A_(2) are v_(1),v_(2) respectively. The difference in the levels of liquid in the two vertical tubes is h.

Answer»

<P>the volume of liquid flowing through the TUBE in unit time is `A_(1)v_(1)`
`v_(2)-v_(1)=sqrt(2gh)`
`v_(2)^(2)=v_(1)^(2)=2gh`
the energy PER unit mass of liquid is the same in both the SECTIONS of the tube.

Solution :Rate of flow`=A_(1)V_(1)`
`(P_(1))/(rho)+(v_(1)^(2))/(2)=(P_(2))/(rho)+(v_(2)^(2))/(2)impliesP_(1)-P_(2)=(rho)/(2)(v_(2)^(2)-v_(1)^(2))`
`impliesv_(2)^(2)-v_(1)^(2)=2gh`
The energy per unit mass of the liquid is the same in both sections.


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