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A liquid flows through a horizontal tube. The velocities of the liquid in the two sections which have area of cross section A_(1) and A_(2) are v_(1),v_(2) respectively. The difference in the levels of liquid in the two vertical tubes is h. |
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Answer» <P>the volume of liquid flowing through the TUBE in unit time is `A_(1)v_(1)` `(P_(1))/(rho)+(v_(1)^(2))/(2)=(P_(2))/(rho)+(v_(2)^(2))/(2)impliesP_(1)-P_(2)=(rho)/(2)(v_(2)^(2)-v_(1)^(2))` `impliesv_(2)^(2)-v_(1)^(2)=2gh` The energy per unit mass of the liquid is the same in both sections. |
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