A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base .If the redius of the vessel is r and angular velocity of rotation is omega, then the difference in the heights of the liquid at the centre of the vessel and the edge is .....

A liquid is kept in a cylindrical vessel which is being rotated about

1.	A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base .If the redius of the vessel is r and angular velocity of rotation is omega, then the difference in the heights of the liquid at the centre of the vessel and the edge is .....
Answer» <html><body><p>`(romega)/(2g)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(2)omega^(2))/(2g)`<br/>`sqrt(2gromega)`<br/>`(omega^(2))/(2gr^(2))`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to Bernoulli.s equation,<br/>`P_(A)+(1)/(2)rhov_(A)^(2)+rhogh_(A)`<br/>`=P_(B)+(1)/(2)rhov_(B)^(2)+rhogh_(B)`<br/>Here , `h_(A)=h_(B)`<br/>`thereforeP_(A)+(1)/(2)rhov_(A)^(2)`<br/>`=P_(B)+(1)/(2)rhov_(B)^(2)`<br/>`thereforeP_(A)-P_(B)=(1)/(2)rho[v_(B)^(2)-v_(A)^(2)]`<br/>Now ,`v_(A)=0,v_(B)-romegaandP_(A)-P_(B)=rhog`<br/>`thereforehrhog=(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/rhor-2993346" style="font-weight:bold;" target="_blank" title="Click to know more about RHOR">RHOR</a>^(2)omega^(2)orh=(r^(2)omega^(2))/(2g)`</body></html>