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A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2 c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture isA. `(2//3) T`B. `(8//5) T`C. `(3//5) T`D. `(3//2) T` |
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Answer» Correct Answer - D Let equilibrium temperature be `theta` `mC(2T-theta)=(m)/(2).2C(theta-T)` `theta=(3T)/(2)` |
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