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A liquid of mass `M` and specific heat `S` is at a temperature `2T`. Another liquid of thermal capacity `1.5 times` the first liquid at a temperature `(T)/(3)` is added to it. The resultant temperature of the mixture will beA. `(2T)/(3)`B. `(T)/(2)`C. `T`D. `(4T)/(3)` |
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Answer» Correct Answer - C Heat lost `=` Heat gained |
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