1.

A liquid rises to 1.0 cm in a capillary tube of radius rv How much will it rise if the cross-sectional area of the capillary tube is doubled?

Answer»

Solution : Let the cross-sectional areas of the TUBES be a and 2a.
`therefore a = pir_(1)^(2), r_(1) = sqrt(a/pi)`
and, `2a = pir_(2)^(2), r_(2) = sqrt((2a)/pi)`
We have, `GAMMA=(hdrg)/2` and `h_(1)=1 CM`.
`therefore` for some same liquid, using the above-given equations, we get
`h_(2)/h_(1) = r_(1)/r_(2) = 1/sqrt(2), h_(2) = 1/sqrt(2) xx 1 = 0.707 cm`


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